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Grade 11 · MCR3U · Functions

MCR3U: Exponent Laws and Rational Exponents

Every exponent law comes from what a power means: ana^n is aa multiplied by itself nn times. Count the factors and the laws follow, and the same counting decides what zero, negative and fractional exponents have to mean.

How It Works

Products and quotients. am×an=am+na^m \times a^n = a^{m + n}, because you are counting all the factors together. am÷an=am−na^m \div a^n = a^{m - n}, because the shared factors cancel. Both laws need the same base.

Power of a power. (am)n=amn(a^m)^n = a^{mn}. A power of a product or a quotient applies to every factor inside: (2x3)4=16x12(2x^3)^4 = 16x^{12}, not 2x122x^{12}.

Zero exponent. a0=1a^0 = 1 for a≠0a \ne 0, since anan=an−n\frac{a^n}{a^n} = a^{n - n} has to equal 11.

Negative exponent. a−n=1ana^{-n} = \frac{1}{a^n}. A negative exponent means reciprocal, not a negative number: 2−3=182^{-3} = \frac{1}{8}. A factor can move across the fraction bar if its exponent changes sign, which is how 4−37−2\frac{4^{-3}}{7^{-2}} becomes 7243\frac{7^2}{4^3}.

Rational exponents. a1n=ana^{\frac{1}{n}} = \sqrt[n]{a}, and amn=(an)ma^{\frac{m}{n}} = (\sqrt[n]{a})^m. The denominator is the root and the numerator is the power. Take the root first to keep the numbers small: 3235=23=832^{\frac{3}{5}} = 2^3 = 8.

A routine for long expressions. Turn every root into a rational exponent. Simplify inside the brackets, apply the outside powers, then combine like bases. Finish with positive exponents only, unless the question says otherwise.

Common slips. −24=−16-2^4 = -16 but (−2)4=16(-2)^4 = 16, because the exponent binds before the minus sign. And there is no law for sums: (a+b)2(a + b)^2 is not a2+b2a^2 + b^2.

5 Worked Examples

Easy first, test level last. Try each one on paper, then open the solution.

  1. Easy

    Simplify x5×x−2x7\frac{x^5 \times x^{-2}}{x^7}, using positive exponents.
    Show solution
    1. Top: x5+(−2)=x3x^{5 + (-2)} = x^3.
    2. Divide: x3−7=x−4x^{3 - 7} = x^{-4}, then take the reciprocal.

    Answer: 1x4\frac{1}{x^4}

  2. Easy

    Evaluate 272327^{\frac{2}{3}}, 16−3416^{-\frac{3}{4}} and (49)−12\left(\frac{4}{9}\right)^{-\frac{1}{2}}.
    Show solution
    1. 2723=(273)2=32=927^{\frac{2}{3}} = (\sqrt[3]{27})^2 = 3^2 = 9.
    2. 16−34=1(164)3=123=1816^{-\frac{3}{4}} = \frac{1}{(\sqrt[4]{16})^3} = \frac{1}{2^3} = \frac{1}{8}.
    3. (49)−12=(94)12=32\left(\frac{4}{9}\right)^{-\frac{1}{2}} = \left(\frac{9}{4}\right)^{\frac{1}{2}} = \frac{3}{2}.

    Answer: 99, 18\frac{1}{8} and 32\frac{3}{2}.

  3. Medium

    Simplify (3a2b−1)3(a−1b)2(3a^2b^{-1})^3(a^{-1}b)^2, using positive exponents.
    Show solution
    1. Apply the outside powers: 27a6b−3×a−2b227a^6b^{-3} \times a^{-2}b^2.
    2. Combine like bases: 27a6−2b−3+2=27a4b−127a^{6 - 2}b^{-3 + 2} = 27a^4b^{-1}.

    Answer: 27a4b\frac{27a^4}{b}

  4. Medium

    Write x73x\frac{\sqrt[3]{x^7}}{\sqrt{x}} as a single power of xx.
    Show solution
    1. Turn the roots into exponents: x73x12\frac{x^{\frac{7}{3}}}{x^{\frac{1}{2}}}.
    2. Subtract: 73−12=146−36=116\frac{7}{3} - \frac{1}{2} = \frac{14}{6} - \frac{3}{6} = \frac{11}{6}.

    Answer: x116x^{\frac{11}{6}}

  5. Test level

    Simplify (8x6y−3)23(16x−2y4)12\frac{(8x^6y^{-3})^{\frac{2}{3}}}{(16x^{-2}y^4)^{\frac{1}{2}}}, using positive exponents.
    Show solution
    1. Top: 823=(83)2=48^{\frac{2}{3}} = (\sqrt[3]{8})^2 = 4, so the top is 4x4y−24x^4y^{-2}.
    2. Bottom: 1612=416^{\frac{1}{2}} = 4, so the bottom is 4x−1y24x^{-1}y^2.
    3. Divide: 44x4−(−1)y−2−2=x5y−4\frac{4}{4}x^{4 - (-1)}y^{-2 - 2} = x^5y^{-4}.

    Answer: x5y4\frac{x^5}{y^4}

Learn It on Martian Lab

Martian Lab teaches this in the Exponent Laws lesson of its MCR3U Exponential Functions unit. Watch it, then take the Exponential Functions practice tests to see if it stuck.

Watch the Exponent Laws lesson free

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