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Grade 11 · MCR3U · Functions

MCR3U: Graphing Exponential Functions

An exponential function y=bxy = b^x, with b>0b > 0 and b≠1b \ne 1, multiplies by the same factor every time xx goes up by 11. Graphing one comes down to a few key points and the asymptote, and every transformation in the unit moves those.

How It Works

The base function. y=2xy = 2^x passes through (−1,12)\left(-1, \frac{1}{2}\right), (0,1)(0, 1), (1,2)(1, 2) and (2,4)(2, 4). It rises from left to right, and to the left it gets closer and closer to the xx-axis without touching it. Its horizontal asymptote is y=0y = 0, its domain is all real numbers and its range is y>0y > 0.

Growth or decay. If b>1b > 1 the graph increases; if 0<b<10 < b < 1 it decreases. y=(12)xy = \left(\frac{1}{2}\right)^x is y=2−xy = 2^{-x}, the reflection of y=2xy = 2^x in the yy-axis.

The transformed form is y=a(b)k(x−d)+cy = a(b)^{k(x - d)} + c, read like any other transformation. aa stretches vertically, and reflects in the xx-axis if it is negative. kk compresses horizontally by a factor of 1k\frac{1}{k}, and reflects in the yy-axis if it is negative. dd shifts right and cc shifts up. Factor kk out of the exponent first: 23x−6=23(x−2)2^{3x - 6} = 2^{3(x - 2)}.

Mapping rule. (x,y)→(xk+d,  ay+c)(x, y) \to \left(\frac{x}{k} + d, \; ay + c\right). Push the key points of the base function through it and join them smoothly.

The asymptote. Only cc moves it. Stretches, reflections and horizontal shifts leave y=0y = 0 where it is, so the new asymptote is y=cy = c. Draw it first, as a dashed line.

Domain and range. The domain stays all real numbers. The range is y>cy > c when a>0a > 0, and y<cy < c when a<0a < 0 because the graph is flipped below the asymptote.

Intercepts. Substitute x=0x = 0 for the yy-intercept: it checks the sketch, and tests often ask for it.

5 Worked Examples

Easy first, test level last. Try each one on paper, then open the solution.

  1. Easy

    Make a table of values for y=3xy = 3^x from x=−2x = -2 to x=2x = 2, and state the asymptote, domain and range.
    Show solution
    1. 3−2=193^{-2} = \frac{1}{9}, 3−1=133^{-1} = \frac{1}{3}, 30=13^0 = 1, 31=33^1 = 3, 32=93^2 = 9.
    2. The values approach 00 to the left but never reach it.

    Answer: Points (−2,19)\left(-2, \frac{1}{9}\right), (−1,13)\left(-1, \frac{1}{3}\right), (0,1)(0, 1), (1,3)(1, 3), (2,9)(2, 9); asymptote y=0y = 0; domain all real numbers; range y>0y > 0.

  2. Easy

    Describe how y=2x+3−4y = 2^{x + 3} - 4 transforms y=2xy = 2^x, and state its asymptote and range.
    Show solution
    1. x+3=x−(−3)x + 3 = x - (-3), so d=−3d = -3: a shift left 33.
    2. c=−4c = -4: a shift down 44, which moves the asymptote to y=−4y = -4.

    Answer: Left 33 and down 44; asymptote y=−4y = -4; range y>−4y > -4.

  3. Medium

    For y=−2(3)x−1+5y = -2(3)^{x - 1} + 5, state the asymptote, domain and range, and find the yy-intercept.
    Show solution
    1. c=5c = 5, so the asymptote is y=5y = 5.
    2. a=−2<0a = -2 < 0 flips the graph below the asymptote, so the range is y<5y < 5. The domain is all real numbers.
    3. At x=0x = 0: y=−2(3)−1+5=−23+5=133y = -2(3)^{-1} + 5 = -\frac{2}{3} + 5 = \frac{13}{3}.

    Answer: Asymptote y=5y = 5; domain all real numbers; range y<5y < 5; yy-intercept 133\frac{13}{3}.

  4. Medium

    Graph y=12(4)2x−4+1y = \frac{1}{2}(4)^{2x - 4} + 1 by mapping the key points (−1,14)\left(-1, \frac{1}{4}\right), (0,1)(0, 1) and (1,4)(1, 4) of y=4xy = 4^x.
    Show solution
    1. Factor the exponent: 2x−4=2(x−2)2x - 4 = 2(x - 2), so a=12a = \frac{1}{2}, k=2k = 2, d=2d = 2, c=1c = 1.
    2. Mapping rule: (x,y)→(x2+2,  y2+1)(x, y) \to \left(\frac{x}{2} + 2, \; \frac{y}{2} + 1\right).
    3. (−1,14)→(32,98)\left(-1, \frac{1}{4}\right) \to \left(\frac{3}{2}, \frac{9}{8}\right), (0,1)→(2,32)(0, 1) \to \left(2, \frac{3}{2}\right), (1,4)→(52,3)(1, 4) \to \left(\frac{5}{2}, 3\right).
    4. The asymptote is y=1y = 1 and the graph rises above it.

    Answer: Points (32,98)\left(\frac{3}{2}, \frac{9}{8}\right), (2,32)\left(2, \frac{3}{2}\right), (52,3)\left(\frac{5}{2}, 3\right); asymptote y=1y = 1; range y>1y > 1.

  5. Test level

    The graph of y=2xy = 2^x is reflected in the xx-axis, compressed horizontally by a factor of 13\frac{1}{3}, then shifted 22 units right and 88 units up. Write its equation, state the asymptote and range, and find both intercepts.
    Show solution
    1. a=−1a = -1, k=3k = 3, d=2d = 2, c=8c = 8: y=−23(x−2)+8y = -2^{3(x - 2)} + 8.
    2. Asymptote y=8y = 8; with a<0a < 0 the range is y<8y < 8.
    3. xx-intercept: 23(x−2)=8=232^{3(x - 2)} = 8 = 2^3, so 3(x−2)=33(x - 2) = 3 and x=3x = 3.
    4. yy-intercept: y=−2−6+8=8−164=51164y = -2^{-6} + 8 = 8 - \frac{1}{64} = \frac{511}{64}.

    Answer: y=−23(x−2)+8y = -2^{3(x - 2)} + 8; asymptote y=8y = 8; range y<8y < 8; xx-intercept 33; yy-intercept 51164≈7.98\frac{511}{64} \approx 7.98.

Learn It on Martian Lab

Martian Lab teaches this in the Transformations of Exponential Functions lesson of its MCR3U Exponential Functions unit. Watch it, then take the Exponential Functions practice tests to see if it stuck.

Watch the Transformations of Exponential Functions lesson free

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