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Grade 12 · MHF4U · Advanced Functions

MHF4U: Solving Exponential Equations

An exponential equation has the unknown in the exponent, as in 2x+3=322^{x + 3} = 32 or 5x=405^x = 40. Getting xx down from the exponent takes one of two moves: write both sides as powers of the same base, or take the logarithm of both sides.

How It Works

When both sides are powers of one base, make the bases match. 4x+1=8x−14^{x + 1} = 8^{x - 1} becomes 22x+2=23x−32^{2x + 2} = 2^{3x - 3}, and two equal powers of the same base have equal exponents: 2x+2=3x−32x + 2 = 3x - 3. This gives an exact answer with no calculator.

When they are not, take the log of both sides. The power law log⁡(an)=nlog⁡a\log(a^n) = n \log a brings the exponent down. From 5x=405^x = 40 you get xlog⁡5=log⁡40x \log 5 = \log 40, so x=log⁡40log⁡5x = \frac{\log 40}{\log 5}. That fraction is the exact answer; round only at the end. Either log⁡\log or ln⁡\ln works, as long as you use the same one on both sides.

When xx is on both sides with different bases, take logs, expand the brackets, and collect the xx terms on one side like any linear equation. The coefficients are logs, but they are just numbers.

When there are two terms with the unknown, look for a quadratic. 4x4^x is (2x)2(2^x)^2, so 4x−2x+1−15=04^x - 2^{x + 1} - 15 = 0 is u2−2u−15=0u^2 - 2u - 15 = 0 with u=2xu = 2^x. Factor, then go back to 2x2^x. A power of a positive base is always positive, so a negative value of uu gives no solution and is rejected.

Check each answer in the original equation. It catches a rejected root you forgot to reject and a rounding slip.

5 Worked Examples

Easy first, test level last. Try each one on paper, then open the solution.

  1. Easy

    Solve 2x+3=322^{x + 3} = 32.
    Show solution
    1. 32=2532 = 2^5, so 2x+3=252^{x + 3} = 2^5.
    2. Equal bases, so equal exponents: x+3=5x + 3 = 5.

    Answer: x=2x = 2

  2. Easy

    Solve 5x=405^x = 40. Give the exact answer and a decimal to three places.
    Show solution
    1. 4040 is not a power of 55, so take the log of both sides: xlog⁡5=log⁡40x \log 5 = \log 40.
    2. x=log⁡40log⁡5≈2.292x = \frac{\log 40}{\log 5} \approx 2.292.
    3. Check: 52.292≈40.05^{2.292} \approx 40.0.

    Answer: x=log⁡40log⁡5≈2.292x = \frac{\log 40}{\log 5} \approx 2.292

  3. Medium

    Solve 4x+1=8x−14^{x + 1} = 8^{x - 1}.
    Show solution
    1. Write both as powers of 22: (22)x+1=(23)x−1(2^2)^{x + 1} = (2^3)^{x - 1}, so 22x+2=23x−32^{2x + 2} = 2^{3x - 3}.
    2. 2x+2=3x−32x + 2 = 3x - 3, so x=5x = 5.
    3. Check: 46=40964^6 = 4096 and 84=40968^4 = 4096.

    Answer: x=5x = 5

  4. Medium

    Solve 32x−1=5x+23^{2x - 1} = 5^{x + 2} to three decimal places.
    Show solution
    1. Take logs: (2x−1)log⁡3=(x+2)log⁡5(2x - 1) \log 3 = (x + 2) \log 5.
    2. Expand: 2xlog⁡3−log⁡3=xlog⁡5+2log⁡52x \log 3 - \log 3 = x \log 5 + 2 \log 5.
    3. Collect the xx terms: x(2log⁡3−log⁡5)=2log⁡5+log⁡3x(2 \log 3 - \log 5) = 2 \log 5 + \log 3.
    4. x=2log⁡5+log⁡32log⁡3−log⁡5=log⁡75log⁡1.8≈7.345x = \frac{2 \log 5 + \log 3}{2 \log 3 - \log 5} = \frac{\log 75}{\log 1.8} \approx 7.345.

    Answer: x=log⁡75log⁡1.8≈7.345x = \frac{\log 75}{\log 1.8} \approx 7.345

  5. Test level

    Solve 4x−2x+1−15=04^x - 2^{x + 1} - 15 = 0.
    Show solution
    1. 4x=(2x)24^x = (2^x)^2 and 2x+1=2⋅2x2^{x + 1} = 2 \cdot 2^x. Let u=2xu = 2^x: u2−2u−15=0u^2 - 2u - 15 = 0.
    2. (u−5)(u+3)=0(u - 5)(u + 3) = 0, so u=5u = 5 or u=−3u = -3.
    3. 2x=−32^x = -3 has no solution, since 2x>02^x > 0. Reject it.
    4. 2x=52^x = 5 gives x=log⁡5log⁡2≈2.322x = \frac{\log 5}{\log 2} \approx 2.322.
    5. Check: 42.322−23.322−15≈25−10−15=04^{2.322} - 2^{3.322} - 15 \approx 25 - 10 - 15 = 0.

    Answer: x=log⁡5log⁡2≈2.322x = \frac{\log 5}{\log 2} \approx 2.322

Learn It on Martian Lab

Martian Lab teaches this in the Logarithmic & Exponential Equations lesson of its MHF4U Exponential & Logarithmic Functions unit. Watch it, then take the Exponential & Logarithmic Functions practice tests to see if it stuck.

Watch the Logarithmic & Exponential Equations lesson free

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